Interpretation In all the blocks of gelatin the rate of penetration of the hydrochloric acid from each side would have been the same but all the blocks take different amounts of time to clear because they are different sizes.
Ethical issues There are no ethical issues associated with this procedure.
The largest block only has 0. V as size increases requires changing to a less compact shape. Extracts of this project must not be included in any projects that you submit for marking. The moonMercury and Mars have radii in the low thousands of kilometers; all three retained heat well enough to be thoroughly differentiated although after a billion years or so they became too cool to show anything more than very localized and infrequent volcanic activity, of which none is evident at present.
Notes 1 and 2. It is important that cells have a large surface area to volume ratio so that they can get enough nutrients into the cell. Higher values are also correlated to shorter fuel ignition times, and hence faster fire spread rates.
Heat, in an aluminium water bath filled with boiling water, with stirring, until the agar solution boils, then allow to cool. By having millions of these alveoli the lungs are able to cram a very large surface area into a small space. Dust explosion Materials with high surface area to volume ratio e.
The lungs have a very large surface area because they contain millions of sacs called alveoli which allow oxygen to diffuse into the bloodstream. This surface area is sufficient for all the oxygen we need to diffuse through it and to let the carbon dioxide out.
The larger blocks have a smaller proportion of surface area than the smaller blocks.
Limitations To help make this experiment more accurate, I repeated it three times for each block size and then used the average of all the results to plot a graph with a line of best fit.
Precautions a All the gelatin used should be taken from the same block to ensure that all the blocks are made up of the same materials.
The concentration of carbon dioxide outside the cell is lower than the concentration in the cell so the carbon dioxide will always dissolve out of the cell.
Doing this could lead to being disqualified from all the subjects that you are taking. A better overall result would be obtained by repeating the experiment more times because any errors in one experiment should be compensated for by the other experiments. When the surface area to volume ratio goes down it takes longer for the hydrochloric acid to diffuse into the cube but if the ratio goes up then the hydrochloric acid diffuses more quickly into the block of gelatin.
Disclaimer This is a real A-level school project and as such is intended for educational or research purposes only. Make the agar blocks in straight-sided dishes or ice cube trays.
The anomalous result was probably due to experimental error as a result of this being the first block size that I used in the experiment. The higher its value, the faster a particle responds to changes in environmental conditions, such as temperature or moisture.
A small cradle could be used to suspend the blocks in the acid which would mean that all six sides of the cube should be in contact with the acid. This reduces their rate of sink and allows them to remain near the surface with less energy expenditure. Preparation a Make up plain technical agar with sodium hydroxide and universal indicator, or with sodium hydroxide and phenolphthalein.
This means that the hydrochloric acid is able to diffuse to the centre of the smallest block much faster than the largest block. The cell membrane is made up of a lipid bi-layer with many proteins integrated into it. This would ensure that diffusion could occur evenly through all the sides of the cube.
Finely ground salt dissolves much more quickly than coarse salt. For example, many aquatic microorganisms have increased surface area to increase their drag in the water.As the size of a cell increases, its ability to facilitate diffusion across its cell membrane decreases.
This is because the internal volume of a growing cell, or any three-dimensional enclosed structure, increases by a greater proportion than its external surface area. If a cell were to grow in.
The surface-area-to-volume ratio, also called the surface-to-volume ratio and variously denoted sa/vol or SA:V, is the amount of surface area per unit volume of an object or collection of objects.
In chemical reactions involving a solid material, the surface area to volume ratio is an important factor for the reactivity, that is, the rate at which the. LAB 04 – Diffusion and Osmosis Objectives: Describe the physical mechanisms of diffusion and osmosis. Understand the relationship between surface area and rate of diffusion.
In walled cells, including fungal and plant cells, the presence of a cell wall. Surface Area to Volume Ratio and the Relation to the Rate of Diffusion Aim and Background This is an experiment to examine how the Surface Area / Volume Ratio affects the rate of diffusion and how this relates to the size and shape of living organisms.
If the surface area of the cell increases, then the rate of diffusion will decrease. Explaining the Hypothesis: When you increase surface area and volume of a cube, the volume increases more rapidly than the surface area. The larger the surface area, the easier is it for molecules to cross the membrane.
Conversely, the smaller the surface area, the more difficult it is for molecules to cross the barrier.
The disparity of water concentration, or difference in water potential, is a large factor in the speed of osmosis.Download